\(\big(a_{n+1}\big)^n=10\big(a_n\big)^{n+1}\quad(n\geq 1)\).
The following is a process computing the general term \(a_n\).
Taking the common logarithm to both sides of the equation gives
\(n\log_{10} a_{n+1}=(n+1)\log_{10}a_n+1\).
Dividing both sides with \(n(n+1)\) gives
\(\dfrac{\log_{10} a_{n+1}}{n+1}=\dfrac{\log_{10}a_n}{n}+
\fbox{\(\;(\alpha)\;\)}\).
Let \(b_n=\dfrac{\log_{10}a_n}{n}\).
Then \(b_1=1\) and
\(b_{n+1}=b_n+ \fbox{\(\;(\alpha)\;\)}\).
The general term of the sequence \(\{b_n\}\) is
\(b_n= \fbox{\(\;(\beta)\;\)}\),
therefore
\(\log_{10}a_n=n\times \fbox{\(\;(\beta)\;\)}\).
Therefore \(a_n=10^{n\times \fbox{\(\;(\beta)\;\)}}\).
Let \(f(n)\) and \(g(n)\) be the correct expression for
\(\alpha\) and \(\beta\) respectively.
What is the value of \(\dfrac{g(10)}{f(4)}\)?